Question

elements,elements in order of decreasing electronegativity,f,c,b,o,te,s

Explanation:

Step1: Recall the trend of electronegativity in the periodic table

Electronegativity increases across a period (from left to right) and decreases down a group.
For the first set \(F,C,B\):

• \(F\) is in group \(17\), \(C\) in group \(14\), \(B\) in group \(13\) of the same period (\(2^{nd}\) period).

So the order is \(F > C> B\)

Step2: For the second set \(O,Te,S\)

• \(O\) and \(S\) are in group \(16\), \(O\) is in \(2^{nd}\) period and \(S\) in \(3^{rd}\) period. \(Te\) is in \(5^{th}\) period of group \(16\)

Since electronegativity decreases down a group, the order is \(O > S> Te\)

Answer:

\(F > C> B\); \(O > S> Te\)