Question

electronegativity is a measure of an atoms ability to attract and bond with electrons. which of the following correctly ranks elements in order of increasing electronegativity? a. chlorine < fluorine < oxygen < nitrogen < carbon < lithium b. lithium < oxygen < carbon < nitrogen < chlorine < fluorine c. fluorine < chlorine < nitrogen < oxygen < carbon < lithium d. lithium < carbon < nitrogen < chlorine < oxygen < fluorine

Explanation:

Step1: Recall electronegativity trend

Electronegativity increases across a period (left to right) and decreases down a group (top to bottom) in the periodic table.

Step2: Analyze each element's position

• Lithium (Li) is a metal, low electronegativity.
• Carbon (C), Nitrogen (N), Oxygen (O) are in period 2, left to right: Li < C < N < O.
• Chlorine (Cl) is in period 3, group 17; Fluorine (F) is in period 2, group 17 (F > Cl as F is above Cl). Also, O (period 2, group 16) has higher electronegativity than Cl? Wait, no: O (3.5) vs Cl (3.0), so O > Cl. Wait, let's list electronegativity values (Pauling scale): Li ≈ 1.0, C ≈ 2.5, N ≈ 3.0, Cl ≈ 3.0, O ≈ 3.5, F ≈ 4.0. Wait, Cl and N have similar? Wait no, N is 3.0, Cl is 3.0? Wait, actually, N (3.0), Cl (3.0), but O (3.5) is higher than both, F (4.0) highest. Now, order: Li (1.0) < C (2.5) < N (3.0) < Cl (3.0)? Wait no, wait the options:

Option D: Li < C < N < Cl < O < F. Let's check values: Li (1.0), C (2.5), N (3.0), Cl (3.0), O (3.5), F (4.0). Wait, but Cl and N have same? But in periodic table, across period 2: Li < B < C < N < O < F. Down group 17: F > Cl > Br > I. So Cl is below F, so F > Cl. O is in period 2, group 16, Cl in period 3, group 17. Electronegativity of O (3.5) is higher than Cl (3.0), so O > Cl. So order: Li (1.0) < C (2.5) < N (3.0) < Cl (3.0) < O (3.5) < F (4.0). Wait, but N and Cl have same? But in the options, D is Li < C < N < Cl < O < F. Let's check other options:

A: Cl < F < O < N < C < Li – wrong, electronegativity increases, so Li should be lowest.

B: Li < O < C < N < Cl < F – wrong, C < N < O, so O should be after N, not before C.

C: F < Cl < N < O < C < Li – wrong, F is highest, Li lowest.

D: Li < C < N < Cl < O < F. Let's check the order: Li (1.0) < C (2.5) < N (3.0) < Cl (3.0) < O (3.5) < F (4.0). Even though N and Cl have similar, but in the options, this is the only one that follows the trend: metals (Li) low, then non-metals in period 2 (C, N, O) increasing, then Cl (which is in period 3, group 17, but O is higher than Cl), then F. Wait, maybe the question has a slight error, but among the options, D is the only one that has Li < C < N (correct, as C < N), then Cl (which is same as N? But O is higher than Cl, so Cl < O, then F. So D is Li < C < N < Cl < O < F. Let's confirm the trend: across period 2: Li (group 1) < B < C (group 14) < N (group 15) < O (group 16) < F (group 17). Down group 17: F > Cl > Br > I. So Cl is below F, so F > Cl. O is in group 16, period 2; Cl in group 17, period 3. Electronegativity of O (3.5) is higher than Cl (3.0), so O > Cl. So the correct order should be Li < C < N < O < Cl? No, wait no: O (3.5) is higher than Cl (3.0), so O > Cl. So the order should be Li < C < N < Cl < O < F? Wait, no, because O is higher than Cl, so Cl should be before O? Wait, no: 3.0 (N) vs 3.0 (Cl), then O (3.5) > Cl (3.0), so Cl < O. So the order is Li (1.0) < C (2.5) < N (3.0) = Cl (3.0) < O (3.5) < F (4.0). So among the options, D is Li < C < N < Cl < O < F, which is the only one that has Li < C < N, then Cl, then O, then F. The other options are wrong:

A: decreasing, wrong.

B: Li < O < C – O is higher than C, so C should be before O, wrong.

C: decreasing, wrong.

So D is correct.

Answer:

D. Lithium < Carbon < Nitrogen < Chlorine < Oxygen < Fluorine