Question

each week capechem, a manufacturer of fine chemicals, uses up 150. kg of compound a and 450. kg of compound b in a reaction with only one product, compound c. what is the maximum theoretical mass of compound c that capechem could ship each week? round your answer to the nearest kilogram. suppose on average the percent yield of c in capechems reactors is 71.%. calculate the average amount of compound c that capechem actually ships each week. round your answer to the nearest kilogram.

Explanation:

Step1: Apply the law of conservation of mass

According to the law of conservation of mass, in a chemical reaction, the total mass of reactants equals the total mass of products.
The mass of reactants \(m = m_A+m_B\), where \(m_A = 150\space kg\) and \(m_B=450\space kg\).
So, \(m = 150 + 450=600\space kg\)

Step2: Calculate the actual yield

The formula for percent yield is \(\text{Percent Yield}=\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times100\%\)
We know that \(\text{Percent Yield} = 71\%\) and \(\text{Theoretical Yield}=600\space kg\)
Rearranging the formula for actual yield: \(\text{Actual Yield}=\frac{\text{Percent Yield}}{100\%}\times\text{Theoretical Yield}\)
Substitute the values: \(\text{Actual Yield}=\frac{71}{100}\times600 = 426\space kg\)

Answer:

600 kg, 426 kg