Question

h₂o
draw the molecule by placing atoms on the grid and connecting them with bonds. include all lone pairs of electrons.

Explanation:

Step1: Determine the central atom

Oxygen (\(O\)) is the central atom as it is more electronegative than hydrogen (\(H\)).

Step2: Calculate the valence electrons

Hydrogen has \(1\) valence electron (\(H:1\)), and oxygen has \(6\) valence electrons (\(O:6\)). For \(H_2O\), total valence electrons \(= 2\times1+6 = 8\).

Step3: Form bonds

Each \(H - O\) bond uses \(2\) electrons. Two \(H - O\) bonds use \(2\times2 = 4\) electrons.

Step4: Distribute lone pairs

Remaining electrons \(=8 - 4=4\). These are distributed as two lone pairs on the oxygen atom.

Answer:

The Lewis structure of \(H_2O\) has an oxygen atom in the center. It is bonded to two hydrogen atoms (\(H - O - H\)). There are two lone pairs of electrons on the oxygen atom.