Question

drag each tile to the correct location. classify the chemical equations as being balanced or not balanced. 2co + 2no → 2co₂ + n₂ 6co₂ + 6h₂o → c₆h₁₂o₆ + o₂ h₂co₃ → h₂o + co₂ 2cu + o₂ → cuo balanced not balanced

Explanation:

Step1: Analyze \( 2CO + 2NO

ightarrow 2CO_2 + N_2 \)
Count atoms: Left - C:2, O:2 + 2 = 4, N:2; Right - C:2, O:2×2 = 4, N:2. Balanced.

Step2: Analyze \( 6CO_2 + 6H_2O

ightarrow C_6H_{12}O_6 + O_2 \)
Count O atoms: Left - \( 6×2 + 6×1 = 18 \); Right - \( 6 + 2x \) (x for \( O_2 \) moles). Wait, correct count: Left O: \( 6\times2 + 6\times1 = 18 \); Right O: \( 6 + 2x \). But in photosynthesis, correct balanced is \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + 6O_2 \). So here \( O_2 \) has 1 mole? No, wait the given equation: Right O: \( 6 + 2\times1 = 8 \)? No, mistake. Wait original equation: Left O: 6×2 (from \( CO_2 \)) + 6×1 (from \( H_2O \)) = 12 + 6 = 18. Right O: 6 (from \( C_6H_{12}O_6 \)) + 2x (from \( O_2 \)). For balance, 18 = 6 + 2x → x = 6. But given equation has \( O_2 \) (no coefficient, so 1 mole? No, the tile shows \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + O_2 \) – so O is not balanced. Wait no, wait maybe I miscalculate. Wait \( C_6H_{12}O_6 \) has 6 O, \( O_2 \) has 2. Left O: 6×2 + 6×1 = 18. Right O: 6 + 2 = 8? No, that's wrong. So this equation is not balanced? Wait no, maybe the tile has a typo? Wait no, let's check again. Wait the given equation: \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + O_2 \). Left O: 62 + 61 = 18. Right O: 6 (from glucose) + 2 (from \( O_2 \)) = 8. Not balanced. Wait but maybe I made a mistake. Wait no, the correct balanced is with 6 \( O_2 \). So this equation is not balanced? Wait no, wait the third equation: \( H_2CO_3
ightarrow H_2O + CO_2 \). Left H:2, C:1, O:3; Right H:2, C:1, O:1 + 2 = 3. Balanced.

Step3: Analyze \( H_2CO_3

ightarrow H_2O + CO_2 \)
Left: H:2, C:1, O:3; Right: H:2, C:1, O:1 + 2 = 3. Balanced.

Step4: Analyze \( 2Cu + O_2

ightarrow CuO \)
Left Cu:2, O:2; Right Cu:1, O:1. Not balanced (needs 2 \( CuO \): \( 2Cu + O_2
ightarrow 2CuO \)). So this is not balanced.

Wait now correct:

Balanced equations:

• \( 2CO + 2NO

ightarrow 2CO_2 + N_2 \) (C:2, O:4, N:2 on both sides)

• \( H_2CO_3

ightarrow H_2O + CO_2 \) (H:2, C:1, O:3 on both sides)

Not Balanced:

• \( 6CO_2 + 6H_2O

ightarrow C_6H_{12}O_6 + O_2 \) (O:18 left, 8 right)

• \( 2Cu + O_2

ightarrow CuO \) (Cu:2 left, 1 right; O:2 left, 1 right)

Wait wait, no: \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + 6O_2 \) is balanced. But the tile shows \( O_2 \) (no coefficient), so it's \( O_2 \) (1 mole), so O is 6 + 2 = 8 vs 18. So not balanced. And \( 2Cu + O_2
ightarrow CuO \): right side needs 2 \( CuO \), so not balanced.

So Balanced: \( 2CO + 2NO
ightarrow 2CO_2 + N_2 \), \( H_2CO_3
ightarrow H_2O + CO_2 \)

Not Balanced: \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + O_2 \), \( 2Cu + O_2
ightarrow CuO \)

Answer:

Balanced: \( 2CO + 2NO
ightarrow 2CO_2 + N_2 \), \( H_2CO_3
ightarrow H_2O + CO_2 \)
Not Balanced: \( 6CO_2 + 6H_2O
ightarrow C_6H_{12}O_6 + O_2 \), \( 2Cu + O_2
ightarrow CuO \)