Question

1. drag and drop the letters to the correct locations. complete the generic single replacement equation. a + _ c → _ + _ c

Explanation:

Step1: Recall Single Replacement Reaction

A single replacement reaction has the form \( \text{Element} + \text{Compound}
ightarrow \text{New Element} + \text{New Compound} \), or generally \( A + BC
ightarrow AC + B \) (if \( A \) is more reactive than \( B \)). Here, the reactants are \( A \) (element) and \( BC \) (compound, with \( B \) as the gray atom and \( C \) as the red atom).

Step2: Identify Atoms in Reaction

In the reactant side, we have element \( A \) and compound \( BC \) (gray is \( B \), red is \( C \)). After reaction, the products should be \( AC \) (compound) and \( B \) (element). So the first gray box (reactant) is \( B \), the first product gray box is \( B \) (the displaced element), and the second product gray box (in the compound) is \( A \) (the replacing element). Wait, correcting: The generic single replacement is \( A + BC
ightarrow B + AC \). So reactant compound is \( BC \) (gray \( B \), red \( C \)), element \( A \). Products: element \( B \) and compound \( AC \). So first reactant gray box: \( B \); first product gray box: \( B \); second product gray box: \( A \).

Step3: Fill the Boxes

• Reactant gray box (next to \( C \)): \( B \) (to make \( BC \))
• First product gray box: \( B \) (displaced element)
• Second product gray box (next to \( C \)): \( A \) (to make \( AC \))

Answer:

Reactant gray box: \( B \); First product gray box: \( B \); Second product gray box: \( A \) (So filling the blanks: left reactant blank: \( B \), first product blank: \( B \), second product blank: \( A \))