Question

differentiate the following function.
$f(x) = -5e^{2x}$
$\frac{d}{dx} \left( -5e^{2x} \
ight) = \square$

Explanation:

Step1: Apply constant multiple rule

$\frac{d}{dx}(-5e^{2x}) = -5 \cdot \frac{d}{dx}(e^{2x})$

Step2: Differentiate exponential function

$\frac{d}{dx}(e^{2x}) = e^{2x} \cdot \frac{d}{dx}(2x) = e^{2x} \cdot 2$

Step3: Combine results

$-5 \cdot 2e^{2x} = -10e^{2x}$

Answer:

$-10e^{2x}$