Question

the difference between two marked values is 5 ml and there are 5 spaces between the marked values. what is the calibration of this graduated cylinder? 1 ml 5 ml 2 ml 10 ml

Explanation:

Step1: Understand the problem

We know the difference between two marked values is 5 mL, and there are 5 spaces between them. We need to find the calibration (the value of each space).

Step2: Calculate the calibration

Calibration = Difference between marked values / Number of spaces between them. So, calibration = $\frac{5\space mL}{5}$ = 1 mL.

Answer:

1 mL