Question

¿cuál es la configuración electrónica de un ion óxido (o²⁻)?
○ 1s²2s²2p⁴
○ 1s²2s²2p⁶3s²
○ 1s²2s²2p²
○ 1s²2s²2p⁶

Explanation:

Step1: Determine electron count for O²⁻

Oxygen atom (O) has 8 electrons. The oxide ion (O²⁻) gains 2 electrons, so total electrons = 8 + 2 = 10.

Step2: Build electron configuration

Fill orbitals in order: 1s (holds 2), 2s (holds 2), 2p (holds 6).

• 1s² (2 electrons)
• 2s² (next 2, total 4)
• 2p⁶ (next 6, total 10).

So configuration is \(1s^2 2s^2 2p^6\).

Answer:

\(1s^2 2s^2 2p^6\) (the option with this configuration, likely the bottom - right or as per the visual: the option \(1s^2 2s^2 2p^6\))