Question

the correct formula for silver iodide is
o agi₂
o si
o ag₂i
o agi

question 8
1 pts
the name of the compound nh₄bro₂ is
o ammonium bromite
o ammonium hypobromite
o ammonium perbromate
o ammonium bromate

Explanation:

For the formula of silver iodide, silver has a +1 charge ($Ag^+$) and iodide has a -1 charge ($I^-$), so they combine in a 1:1 ratio to form $AgI$. For $NH_4BrO_2$, $NH_4^+$ is the ammonium ion and $BrO_2^-$ is the bromite ion, so the compound is ammonium bromite.

Answer:

The correct formula for silver iodide: D. $AgI$
The name of the compound $NH_4BrO_2$: A. ammonium bromite