Question

correct
acid base reactions form water when an acid combines with a base. these reactions occur in food, drinks, medicines, and household chemicals
part b
h₂so₄(aq) + koh(aq) →
express your answer as a chemical equation including phases.
h₂so₄(aq) + 2koh(aq) → k₂so₄(aq) + 2h₂o(l)
previous answer
correct
acid base reactions form water when an acid combines with a base. these reactions occur when food, drinks, medicines, and household chemicals
part c
hclo₄(aq) + naoh(aq) →
express your answer as a chemical equation including phases.
a chemical reaction does not occur for this question
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Explanation:

Step1: Identify the acid - base reaction products

In an acid - base reaction, the general form is \( \text{acid}+\text{base}\to\text{salt}+\text{water} \). For \( \text{HClO}_{4}(aq)+\text{NaOH}(aq)\), \( \text{HClO}_{4}\) is an acid (\(H^{+}\) donor) and \( \text{NaOH}\) is a base (\(OH^{-}\) donor). The \(H^{+}\) from \( \text{HClO}_{4}\) and \(OH^{-}\) from \( \text{NaOH}\) combine to form \(H_{2}O\). The remaining ions \(Na^{+}\) and \(ClO_{4}^{-}\) combine to form the salt \( \text{NaClO}_{4}\).

Step2: Write the balanced chemical equation

The unbalanced equation is \( \text{HClO}_{4}(aq)+\text{NaOH}(aq)\to\text{NaClO}_{4}(aq)+\text{H}_{2}O(l)\)
Count the number of each type of atom on both sides.

• For \(H\): 1 + 1 (in \( \text{HClO}_{4}\) and \( \text{NaOH}\)) on the left and 2 (in \(H_{2}O\)) on the right.
• For \(Na\): 1 (in \( \text{NaOH}\)) on the left and 1 (in \( \text{NaClO}_{4}\)) on the right.
• For \(ClO_{4}\): 1 (in \( \text{HClO}_{4}\)) on the left and 1 (in \( \text{NaClO}_{4}\)) on the right.
• For \(O\): 4 (in \( \text{HClO}_{4}\))+1 (in \( \text{NaOH}\)) = 5 on the left and 4 (in \( \text{NaClO}_{4}\)) + 1 (in \(H_{2}O\)) = 5 on the right.

The equation \( \text{HClO}_{4}(aq)+\text{NaOH}(aq)\to\text{NaClO}_{4}(aq)+\text{H}_{2}O(l)\) is already balanced.

Answer:

\( \text{HClO}_{4}(aq)+\text{NaOH}(aq)\to\text{NaClO}_{4}(aq)+\text{H}_{2}O(l)\)