Question

construct the expression for ksp for solid ba₃(po₄)₂ in aqueous solution. ba₃(po₄)₂(s) ⇌ 3 ba²⁺(aq) + 2 po₄³⁻(aq) based on your knowledge of how the solid will dissociate in aqueous solution, construct the expression for the solubility constant, ksp. each reaction participant must be represented by one tile. ksp =

Explanation:

Step1: Write the general formula for \(K_{sp}\)

For a reaction \(A_xB_y(s)
ightleftharpoons xA^{m +}(aq)+yB^{n -}(aq)\), \(K_{sp}=[A^{m +}]^x[B^{n -}]^y\)

Step2: Identify \(x\), \(y\), \(A^{m +}\), and \(B^{n -}\) for \(Ba_3(PO_4)_2\)

In the reaction \(Ba_3(PO_4)_2(s)
ightleftharpoons3Ba^{2 +}(aq)+2PO_4^{3 -}(aq)\), \(x = 3\), \(y = 2\), \(A^{m+}=Ba^{2+}\), \(B^{n -}=PO_4^{3 -}\)

Step3: Substitute into the \(K_{sp}\) formula

\(K_{sp}=[Ba^{2 +}]^3[PO_4^{3 -}]^2\)

Answer:

\(K_{sp}=[Ba^{2 +}]^3[PO_4^{3 -}]^2\)