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consider the reaction $\\ce{h2so4(aq) + h2o(l) -> h3o+(aq) + hso4-(aq)}…

Question

consider the reaction $\ce{h2so4(aq) + h2o(l) -> h3o+(aq) + hso4-(aq)}$. which species is the conjugate base of the acid $\ce{h2so4}$? (note: the equation given is correct)

  1. $\ce{h2so4(aq)}$
  1. $\ce{h2o(l)}$
  1. $\ce{h3o+(aq)}$
  1. $\ce{hso4-}$

Explanation:

Step1: Recall Conjugate Base Definition

A conjugate base is formed when an acid donates a proton ($\ce{H^+}$).

Step2: Analyze the Reaction

In the reaction $\ce{H2SO4(aq) + H2O(l) -> H3O+(aq) + HSO4^-(aq)}$, $\ce{H2SO4}$ donates a proton ($\ce{H^+}$) to $\ce{H2O}$. After donating a proton, $\ce{H2SO4}$ becomes $\ce{HSO4^-}$.

Step3: Evaluate Options

  • Option 1: $\ce{H2SO4}$ is the acid, not its conjugate base.
  • Option 2: $\ce{H2O}$ is a base here, not related to $\ce{H2SO4}$'s conjugate base.
  • Option 3: $\ce{H3O+}$ is the conjugate acid of $\ce{H2O}$, not related to $\ce{H2SO4}$.
  • Option 4: $\ce{HSO4^-}$ is what $\ce{H2SO4}$ becomes after losing a proton, so it's the conjugate base.

Answer:

  1. $\ce{HSO4^-}$