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consider the reaction of 75.0 ml of 0.350 m c₅h₅n (kb = 1.7 x 10⁻⁹) wit…

Question

consider the reaction of 75.0 ml of 0.350 m c₅h₅n (kb = 1.7 x 10⁻⁹) with 100.0 ml of 0.425 m hcl.
what would the total volume of the solution be after the reaction, in ml?

Explanation:

Step1: Add the volumes of the two solutions

When two solutions are mixed, the total volume \(V_{total}\) is the sum of the volumes of each solution.
\(V_{total}=V_{C_5H_5N}+V_{HCl}\)
Given \(V_{C_5H_5N} = 75.0\space mL\) and \(V_{HCl}=100.0\space mL\)

Step2: Calculate the total volume

\(V_{total}=75.0\space mL + 100.0\space mL\)
\(V_{total}=175.0\space mL\)

Answer:

\(175.0\space mL\)