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consider the function $f(x) = -2x^2 - 12x + 10$. for $f(x)$, the vertex…

Question

consider the function $f(x) = -2x^2 - 12x + 10$. for $f(x)$, the vertex is a \bigcirc minimum value \bigcirc maximum value

Explanation:

Step1: Analyze the coefficient of \(x^2\)

For a quadratic function \(f(x) = ax^2 + bx + c\), the sign of \(a\) determines the direction the parabola opens. Here, \(a=-2\). Since \(a < 0\), the parabola opens downward.

Step2: Determine vertex type

A parabola opening downward has its vertex at the highest point, so the vertex represents a maximum value.

Answer:

maximum value (the option: maximum value)