Question

consider the following pairs of elements and the binary compounds they are likely to form.
part 1 of 4
al and br
is the compound likely to be ionic or covalent? select the single best answer.
ionic
covalent
part: 1 / 4
part 2 of 4
write the compounds empirical formula and name.
empirical formula:
name:

Explanation:

Step1: Determine the type of bond

Aluminum (Al) is a metal and bromine (Br) is a non - metal. Ionic bonds typically form between metals and non - metals. In an ionic bond, electrons are transferred from the metal to the non - metal. Aluminum has a tendency to lose electrons (it forms \(Al^{3+}\) ions) and bromine has a tendency to gain electrons (it forms \(Br^{-}\) ions).

Step2: Write the empirical formula

Using the criss - cross method for ionic compounds. The charge of \(Al^{3+}\) is \(+ 3\) and the charge of \(Br^{-}\) is \(-1\). To balance the charges, we need 3 \(Br^{-}\) ions for every 1 \(Al^{3+}\) ion. So the empirical formula is \(AlBr_{3}\).

Step3: Name the compound

For ionic compounds, we name the metal first (aluminum) and then the non - metal with the suffix “-ide” (bromide). So the name is aluminum bromide.

Answer:

• Part 1: ionic
• Part 2:
• Empirical formula: \(AlBr_{3}\)
• Name: aluminum bromide