Question

consider the following intermediate chemical equations.
c(s) + \\(\frac{1}{2}\\)o₂(g) → co(g)
co(g) + \\(\frac{1}{2}\\)o₂(g) → co₂(g)
how will oxygen appear in the final chemical equation?
○ o₂(g) as a product
○ o₂(g) as a reactant
○ o(g) as a product
○ 2o(g) as a reactant

Explanation:

Step1: Add the two equations

Add the left - hand sides and the right - hand sides of the two given equations:
Left - hand side: \(C(s)+\frac{1}{2}O_2(g)+CO(g)+\frac{1}{2}O_2(g)\)
Right - hand side: \(CO(g)+CO_2(g)\)

Step2: Simplify the equation

Simplify the left - hand side and the right - hand side. The \(CO(g)\) on the left and right can be canceled out.
For the oxygen terms: \(\frac{1}{2}O_2(g)+\frac{1}{2}O_2(g)=O_2(g)\)
The simplified equation is \(C(s)+O_2(g)
ightarrow CO_2(g)\)
So, oxygen (\(O_2(g)\)) appears as a reactant.

Answer:

B. \(O_2(g)\) as a reactant (assuming the options are labeled as A, B, C, D with B being \(O_2(g)\) as a reactant)