the conservation of matter can be demonstrated by using chemical equations. which chemical equation demonstrates the conservation of matter?
2sn + 4hno₃ → sno₂ + 4no₂ + h₂o
i₂ + 5cl₂ + 6h₂o → 2hio₃ + 10hcl
cl + 4na → 4nacl
4p + 5hno₃ → 5no + 3h₃po₄

Question

Accepted Answer

# Explanation:
## Step1: Check the number of atoms for each element in the first equation
- For $Sn$: Left - hand side has $2$ atoms, right - hand side has $1$ atom.
- For $H$: Left - hand side has $4$ atoms, right - hand side has $2$ atoms.
- For $N$: Left - hand side has $4$ atoms, right - hand side has $4$ atoms.
- For $O$: Left - hand side has $12$ atoms ($4\times3$ from $HNO_3$), right - hand side has $2 + 8+1=11$ atoms ($2$ from $SnO_2$, $8$ from $4NO_2$ and $1$ from $H_2O$).
## Step2: Check the number of atoms for each element in the second equation
- For $I$: Left - hand side has $2$ atoms ($I_2$), right - hand side has $2$ atoms ($2HIO_3$).
- For $Cl$: Left - hand side has $10$ atoms ($5Cl_2$), right - hand side has $10$ atoms ($10HCl$).
- For $H$: Left - hand side has $12$ atoms ($6H_2O$), right - hand side has $2 + 10=12$ atoms ($2HIO_3$ and $10HCl$).
- For $O$: Left - hand side has $6$ atoms ($6H_2O$), right - hand side has $6$ atoms ($2HIO_3$).
## Step3: Check the number of atoms for each element in the third equation
- For $Cl$: Left - hand side has $1$ atom, right - hand side has $4$ atoms ($4NaCl$).
## Step4: Check the number of atoms for each element in the fourth equation
- For $P$: Left - hand side has $4$ atoms, right - hand side has $3$ atoms ($3H_3PO_4$).
- For $H$: Left - hand side has $5$ atoms ($5HNO_3$), right - hand side has $9$ atoms ($3H_3PO_4$).
- For $N$: Left - hand side has $5$ atoms ($5HNO_3$), right - hand side has $5$ atoms ($5NO$).
- For $O$: Left - hand side has $15$ atoms ($5HNO_3$), right - hand side has $5 + 12=17$ atoms ($5NO$ and $3H_3PO_4$).

# Answer:
$I_2 + 5Cl_2+6H_2O
ightarrow2HIO_3 + 10HCl$

Sovi.AI - AI Math Tutor

QUESTION IMAGE

Question

Explanation:

Step1: Check the number of atoms for each element in the first equation

Step2: Check the number of atoms for each element in the second equation

Step3: Check the number of atoms for each element in the third equation

Step4: Check the number of atoms for each element in the fourth equation

Answer: