Question

complete the table below by writing the symbols for the cation and anion that make up each ionic compound. the first row has been completed for you.
ionic compound cation anion
nacl na+ cl-
v(oh)2 v₁
co(no3)2
fes
nh4f

Explanation:

Step1: Analyze \(V(OH)_2\)

Ionic compounds are made of cations and anions. In \(V(OH)_2\), the hydroxide ion \((OH^-)\) is the anion. Since there are 2 \(OH^-\) ions (each with a - 1 charge), the cation \(V\) must have a + 2 charge. So the cation is \(V^{2 +}\) and the anion is \(OH^-\).

Step2: Analyze \(Co(NO_3)_2\)

In \(Co(NO_3)_2\), the nitrate ion \((NO_3^-)\) is the anion. With 2 \(NO_3^-\) ions (each - 1 charge), the cobalt cation \(Co\) has a + 2 charge. So the cation is \(Co^{2+}\) and the anion is \(NO_3^-\).

Step3: Analyze \(FeS\)

In \(FeS\), the sulfide ion \((S^{2-})\) is the anion. To balance the - 2 charge of \(S^{2-}\), the iron cation \(Fe\) has a + 2 charge. So the cation is \(Fe^{2+}\) and the anion is \(S^{2-}\).

Step4: Analyze \(NH_4F\)

In \(NH_4F\), the fluoride ion \((F^-)\) is the anion. The ammonium ion \((NH_4^+)\) is the cation. So the cation is \(NH_4^+\) and the anion is \(F^-\).

Answer:

ionic compound	cation	anion
\(Co(NO_3)_2\)	\(Co^{2+}\)	\(NO_3^-\)
\(FeS\)	\(Fe^{2+}\)	\(S^{2-}\)
\(NH_4F\)	\(NH_4^+\)	\(F^-\)