Question

1. complete the following table:

\

$$\begin{tabular}{|l|l|} \\hline \\textbf{name} & \\textbf{formula} \\\\ \\hline & \\text{hg}_3\\text{p}_2 \\\\ \\hline \\text{dinitrogen monoxide} & \\\\ \\hline & \\text{na}_2\\text{cro}_4 \\\\ \\hline \\text{iron(ii) nitride} & \\\\ \\hline & \\text{ba(clo}_4)_2 \\\\ \\hline \\text{phosphorus triiodide} & \\\\ \\hline & \\text{ca(hco}_3)_2 \\\\ \\hline \\text{magnesium fluoride} & \\\\ \\hline & \\text{n}_2\\text{o}_3 \\\\ \\hline \\text{cobalt(iii) iodide} & \\\\ \\hline \\end{tabular}$$

Explanation:

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<reasoning>

Identify naming rules

We need to complete the table by matching chemical names with formulas.

• Ionic compounds use Roman numerals for variable-charge metals, and no prefixes.
• Covalent compounds use Greek prefixes (mono-, di-, tri-, etc.).
• Polyatomic ions retain their specific names (e.g., chromate, perchlorate, bicarbonate).

Analyze each row

1. Row 1: Formula is \(\text{Hg}_3\text{P}_2\). Mercury is a metal, phosphorus is a nonmetal. Mercury can have multiple charges. Since phosphide is \(\text{P}^{3-}\), three mercury ions must balance two phosphide ions (\(2 \times 3- = -6\)), so each mercury has a \(2+\) charge: \(\text{Hg}^{2+}\). The correct IUPAC name is mercury(II) phosphide.
2. Row 2: Name is dinitrogen monoxide. This is a covalent compound. "Di-" means 2 nitrogen, "mono-" means 1 oxygen. Formula: \(\text{N}_2\text{O}\).
3. Row 3: Formula is \(\text{Na}_2\text{CrO}_4\). Sodium (\(\text{Na}^+\)) and chromate (\(\text{CrO}_4^{2-}\)). Name: sodium chromate.
4. Row 4: Name is iron(II) nitride. Iron(II) is \(\text{Fe}^{2+}\), nitride is \(\text{N}^{3-}\). To balance charges, we need three \(\text{Fe}^{2+}\) and two \(\text{N}^{3-}\). Formula: \(\text{Fe}_3\text{N}_2\).
5. Row 5: Formula is \(\text{Ba(ClO}_4)_2\). Barium (\(\text{Ba}^{2+}\)) and perchlorate (\(\text{ClO}_4^-\)). Name: barium perchlorate.
6. Row 6: Name is phosphorus triiodide. One phosphorus, three iodines. Formula: \(\text{PI}_3\).
7. Row 7: Formula is \(\text{Ca(HCO}_3)_2\). Calcium (\(\text{Ca}^{2+}\)) and hydrogen carbonate (or bicarbonate, \(\text{HCO}_3^-\)). Name: calcium hydrogen carbonate (or calcium bicarbonate).
8. Row 8: Name is magnesium fluoride. Magnesium (\(\text{Mg}^{2+}\)) and fluoride (\(\text{F}^-\)). Formula: \(\text{MgF}_2\).
9. Row 9: Formula is \(\text{N}_2\text{O}_3\). Two nitrogens, three oxygens. Name: dinitrogen trioxide.
10. Row 10: Name is cobalt(III) iodide. Cobalt(III) is \(\text{Co}^{3+}\), iodide is \(\text{I}^-\). Formula: \(\text{CoI}_3\).

</reasoning>

<answer>

Name	Formula
dinitrogen monoxide	\(\text{N}_2\text{O}\)
sodium chromate	\(\text{Na}_2\text{CrO}_4\)
iron(II) nitride	\(\text{Fe}_3\text{N}_2\)
barium perchlorate	\(\text{Ba(ClO}_4)_2\)
phosphorus triiodide	\(\text{PI}_3\)
calcium hydrogen carbonate (or calcium bicarbonate)	\(\text{Ca(HCO}_3)_2\)
magnesium fluoride	\(\text{MgF}_2\)
dinitrogen trioxide	\(\text{N}_2\text{O}_3\)
cobalt(III) iodide	\(\text{CoI}_3\)

</answer>

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Answer:

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<reasoning>

Identify naming rules

We need to complete the table by matching chemical names with formulas.

• Ionic compounds use Roman numerals for variable-charge metals, and no prefixes.
• Covalent compounds use Greek prefixes (mono-, di-, tri-, etc.).
• Polyatomic ions retain their specific names (e.g., chromate, perchlorate, bicarbonate).

Analyze each row

1. Row 1: Formula is \(\text{Hg}_3\text{P}_2\). Mercury is a metal, phosphorus is a nonmetal. Mercury can have multiple charges. Since phosphide is \(\text{P}^{3-}\), three mercury ions must balance two phosphide ions (\(2 \times 3- = -6\)), so each mercury has a \(2+\) charge: \(\text{Hg}^{2+}\). The correct IUPAC name is mercury(II) phosphide.
2. Row 2: Name is dinitrogen monoxide. This is a covalent compound. "Di-" means 2 nitrogen, "mono-" means 1 oxygen. Formula: \(\text{N}_2\text{O}\).
3. Row 3: Formula is \(\text{Na}_2\text{CrO}_4\). Sodium (\(\text{Na}^+\)) and chromate (\(\text{CrO}_4^{2-}\)). Name: sodium chromate.
4. Row 4: Name is iron(II) nitride. Iron(II) is \(\text{Fe}^{2+}\), nitride is \(\text{N}^{3-}\). To balance charges, we need three \(\text{Fe}^{2+}\) and two \(\text{N}^{3-}\). Formula: \(\text{Fe}_3\text{N}_2\).
5. Row 5: Formula is \(\text{Ba(ClO}_4)_2\). Barium (\(\text{Ba}^{2+}\)) and perchlorate (\(\text{ClO}_4^-\)). Name: barium perchlorate.
6. Row 6: Name is phosphorus triiodide. One phosphorus, three iodines. Formula: \(\text{PI}_3\).
7. Row 7: Formula is \(\text{Ca(HCO}_3)_2\). Calcium (\(\text{Ca}^{2+}\)) and hydrogen carbonate (or bicarbonate, \(\text{HCO}_3^-\)). Name: calcium hydrogen carbonate (or calcium bicarbonate).
8. Row 8: Name is magnesium fluoride. Magnesium (\(\text{Mg}^{2+}\)) and fluoride (\(\text{F}^-\)). Formula: \(\text{MgF}_2\).
9. Row 9: Formula is \(\text{N}_2\text{O}_3\). Two nitrogens, three oxygens. Name: dinitrogen trioxide.
10. Row 10: Name is cobalt(III) iodide. Cobalt(III) is \(\text{Co}^{3+}\), iodide is \(\text{I}^-\). Formula: \(\text{CoI}_3\).

</reasoning>

<answer>

Name	Formula
dinitrogen monoxide	\(\text{N}_2\text{O}\)
sodium chromate	\(\text{Na}_2\text{CrO}_4\)
iron(II) nitride	\(\text{Fe}_3\text{N}_2\)
barium perchlorate	\(\text{Ba(ClO}_4)_2\)
phosphorus triiodide	\(\text{PI}_3\)
calcium hydrogen carbonate (or calcium bicarbonate)	\(\text{Ca(HCO}_3)_2\)
magnesium fluoride	\(\text{MgF}_2\)
dinitrogen trioxide	\(\text{N}_2\text{O}_3\)
cobalt(III) iodide	\(\text{CoI}_3\)

</answer>

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