Question

complete the electron configuration for n.
electron configuration: he

Explanation:

Step1: Determine the atomic number of N

The atomic number of nitrogen (N) is 7. Helium (\(He\)) has 2 electrons. So the remaining number of electrons for the part after \([He]\) is \(7 - 2=5\).

Step2: Fill the orbitals

The next orbitals are \(2s\) and \(2p\). The \(2s\) orbital can hold 2 electrons and the \(2p\) orbital can hold 3 electrons. So the electron - configuration after \([He]\) is \(2s^{2}2p^{3}\)

Answer:

\(2s^{2}2p^{3}\)