QUESTION IMAGE
Question
y = x² + 3
column by column
x | x² | y = x² + 3
-3 | |
-2 | |
-1 | |
0 | |
1 | |
2 | |
3 | |
try
Step1: Calculate \( x^2 \) for \( x = -3 \)
We know that for any real number \( a \), \( (-a)^2=a^2 \). So when \( x = - 3 \), we calculate \( x^{2}=(-3)^{2}\). By the definition of squaring a number, \( (-3)\times(-3) = 9 \). So the value of \( x^{2} \) when \( x=-3 \) is \( 9 \).
Step2: Calculate \( y=x^{2}+3 \) for \( x = - 3 \)
We already found that \( x^{2}=9 \) when \( x = - 3 \). Now we substitute \( x^{2}=9 \) into the equation \( y=x^{2}+3 \). So \( y=9 + 3=12 \).
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For the \( x=-3 \) row, the value of \( x^{2} \) is \( 9 \) and the value of \( y = x^{2}+3 \) is \( 12 \).