Question

a chemist prepares a solution of mercury(ii) iodide (hgi₂) by weighing out 0.0107 g of mercury(ii) iodide into a 350. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in g/l of the chemists mercury(ii) iodide solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Convert volume from mL to L

Since \(1\ \text{L} = 1000\ \text{mL}\), then \(V=350\ \text{mL}=\frac{350}{1000}\ \text{L}=0.350\ \text{L}\)

Step2: Calculate the concentration \(c\)

The formula for concentration \(c=\frac{m}{V}\), where \(m = 0.0107\ \text{g}\) (mass of solute) and \(V\) (volume of solution). Substitute the values: \(c=\frac{0.0107\ \text{g}}{0.350\ \text{L}}\)

$$c=\frac{0.0107}{0.350}\ \text{g/L}\approx0.0306\ \text{g/L}$$

Answer:

\(0.0306\ \text{g/L}\)