Question

a chemist prepares a solution of barium chlorate (ba(clo₃)₂) by weighing out 14.9 g of barium chlorate into a 50. ml volumetric flask and filling the flask to the mark with water.
calculate the concentration in g/l of the chemists barium chlorate solution. be sure your answer has the correct number of significant digits.

Explanation:

Step1: Convert volume from mL to L

We know that \(1\space L = 1000\space mL\). So for \(V = 50\space mL\), we use the conversion factor \(V=\frac{50}{1000}\space L=0.05\space L\)

Step2: Calculate the concentration

The formula for concentration \(C\) (in \(g/L\)) is \(C=\frac{m}{V}\), where \(m = 14.9\space g\) (mass of solute) and \(V\) is the volume of the solution in liters.
Substitute the values: \(C=\frac{14.9\space g}{0.05\space L}\)

$$C=\frac{14.9}{0.05}\space g/L= 298\space g/L$$

Answer:

\(298\space g/L\)