Question

this is the chemical formula for diethyl ether: $(ch_{3}ch_{2})_{2}o$. calculate the mass percent of hydrogen in diethyl ether. round your answer to the nearest percentage.

Explanation:

Step1: Calculate the molar mass of diethyl ether

The chemical formula \((CH_3CH_2)_2O\) can be rewritten as \(C_4H_{10}O\).
The molar mass of \(C\) is \(12.01\ g/mol\), of \(H\) is \(1.008\ g/mol\), and of \(O\) is \(16.00\ g/mol\).
The molar mass of \(C_4H_{10}O\) is \(M=(4\times12.01)+(10\times1.008)+16.00\)
\(M = 48.04+10.08 + 16.00=74.12\ g/mol\)

Step2: Calculate the mass of hydrogen in one mole of diethyl ether

The mass of hydrogen in one mole of \(C_4H_{10}O\) is \(m_H=10\times1.008 = 10.08\ g\)

Step3: Calculate the mass percent of hydrogen

The mass percent of \(H\) is \(\text{Mass}\%=\frac{m_H}{M}\times100\%=\frac{10.08}{74.12}\times100\%\)
\(\text{Mass}\%=\frac{1008}{74.12}\% \approx 13.6\%\)

Answer:

\(14\%\)