Question

ch₄ + 2o₂ → co₂ + 2h₂o
c =
h =
o =
c =
h =
o =

Explanation:

Step1: Count atoms on reactant side

For \(CH_4\): \(1\) C, \(4\) H. For \(2O_2\): \(2\times2 = 4\) O.

Step2: Count atoms on product side

For \(CO_2\): \(1\) C, \(2\) O. For \(2H_2O\): \(2\times2 = 4\) H, \(2\times1 = 2\) O. Total O: \(2 + 2=4\).

Answer:

Left side: \(C = 1\), \(H = 4\), \(O = 4\). Right side: \(C = 1\), \(H = 4\), \(O = 4\).