Question

1. calculate the number of moles of hcl in 40.0 ml of 1.0 m hcl and the number of moles of naoh in 15.0 ml of 1.0 m naoh.

Explanation:

Step1: Convert volume to liters

For HCl: \( V_{HCl}=40.0\space mL = 40.0\times10^{- 3}\space L\)
For NaOH: \( V_{NaOH}=15.0\space mL=15.0\times 10^{-3}\space L\)

Step2: Use the formula \(n = M\times V\)

For HCl: \(n_{HCl}=M_{HCl}\times V_{HCl}\)
Given \(M_{HCl} = 1.0\space M\), \(n_{HCl}=1.0\space M\times40.0\times 10^{-3}\space L = 0.040\space mol\)
For NaOH: \(n_{NaOH}=M_{NaOH}\times V_{NaOH}\)
Given \(M_{NaOH}=1.0\space M\), \(n_{NaOH}=1.0\space M\times15.0\times 10^{-3}\space L=0.015\space mol\)

Answer:

The number of moles of HCl is \(0.040\space mol\) and the number of moles of NaOH is \(0.015\space mol\)