Question

bread
reach performance task student
flour contains 0.05% glucose. the grams of glucose provided in the table below correspond to the
amounts of flour provided for each recipe.
c. using the molar masses from question 2a, calculate the amount of moles of glucose in
the recipes.
glucose - c₆h₁₂o₆
oxygen - o₂
(please show your work and include units)
amys
recipe
elis
recipe
mass
(grams)
37.5 grams
60 grams
workspace
dimensional analysis method:
37.5 grams c₆h₁₂o₆ x
1
you can use a different method and show
your work here:
dimensional analysis method:
60 grams c₆h₁₂o₆ x
1
you can use a different method and show
your work here:
moles
moles
1.249 mol
0.022 mol

Explanation:

Step1: Calculer la masse molaire du glucose \(C_6H_{12}O_6\)

La masse atomique de \(C = 12\space g/mol\), \(H= 1\space g/mol\), \(O = 16\space g/mol\)
Masse molaire \(M\) de \(C_6H_{12}O_6=6\times12 + 12\times1+6\times16\)
\(M=(72 + 12+96)\space g/mol=180\space g/mol\)

Step2: Calculer le nombre de moles pour la recette d'Amy

Formule : \(n=\frac{m}{M}\), où \(m = 37.5\space g\) et \(M = 180\space g/mol\)
\(n=\frac{37.5\space g}{180\space g/mol}=\frac{37.5}{180}\space mol\approx0.208\space mol\)
En utilisant la méthode d'analyse dimensionnelle : \(37.5\space g\space C_6H_{12}O_6\times\frac{1\space mol\space C_6H_{12}O_6}{180\space g\space C_6H_{12}O_6}=0.208\space mol\)

Step3: Calculer le nombre de moles pour la recette d'Eli

Formule : \(n=\frac{m}{M}\), où \(m = 60\space g\) et \(M = 180\space g/mol\)
\(n=\frac{60\space g}{180\space g/mol}=\frac{60}{180}\space mol=\frac{1}{3}\space mol\approx0.333\space mol\)
En utilisant la méthode d'analyse dimensionnelle : \(60\space g\space C_6H_{12}O_6\times\frac{1\space mol\space C_6H_{12}O_6}{180\space g\space C_6H_{12}O_6}=0.333\space mol\)

Answer:

Pour la recette d'Amy : \(0.208\space mol\)
Pour la recette d'Eli : \(0.333\space mol\)