Question

a box has 7 candies: 4 chocolate and 3 mint. if 1 candy is drawn, replaced, and 1 is drawn again, what is the probability of getting chocolate, then mint? event a: chocolate on 1st draw event b: mint on 2nd draw p(a, then b) = ?/ give your answer as a fraction in simplest form. compound probability independent events p(a then b) = p(a) · p(b)

Explanation:

Step1: Calculate P(A)

There are 4 chocolate candies out of 7 total, so $P(A) = \frac{4}{7}$.

Step2: Calculate P(B)

There are 3 mint candies out of 7 total, so $P(B) = \frac{3}{7}$.

Step3: Compute P(A then B)

Since events are independent, multiply probabilities: $P(A) \times P(B) = \frac{4}{7} \times \frac{3}{7} = \frac{12}{49}$.

Answer:

$\frac{12}{49}$