Question

based on the following calculator output, determine the population standard deviation of the dataset, rounding to the nearest 100th if necessary.
1-var-stats
\\(\bar{x} = 97.65263157894736\\)
\\(\sigma x = 9277\\)
\\(\sigma x^2 = 915523\\)
\\(sx = 10.10557926903856\\)
\\(\sigma x = 10.052251301707841\\)
\\(n = 95\\)
\\(\text{minx} = 77\\)
\\(q_1 = 89\\)
\\(\text{med} = 97\\)
\\(q_3 = 106\\)
\\(\text{maxx} = 130\\)

Explanation:

Step1: Identify population std dev symbol

In 1 - Var - Stats, \(\sigma x\) represents population standard deviation.

Step2: Round \(\sigma x\) to nearest hundredth

Given \(\sigma x = 10.052251301707841\). To round to the nearest hundredth (two decimal places), look at the thousandth place (digit 2). Since \(2<5\), we keep the hundredth place as is. So \(10.052251301707841\approx10.05\).

Answer:

\(10.05\)