Question

based on the data provided below, which student has the most precise data?
student melting point data
trial 1 student a: 183.5°c, student b: 190.0°c, student c: 181.3°c
trial 2 student a: 185.9°c, student b: 183.3°c, student c: 182.0°c
trial 3 student a: 184.6°c, student b: 187.1°c, student c: 181.7°c
mean student a: 184.7°c, student b: 186.8°c, student c: 181.6°c
sucrose melting point (accepted value) 186°c
which student has the most precise data?
options: student c, cannot be determined, student a, stude

Explanation:

Step1: Recall Precision Definition

Precision in data refers to the consistency (closeness) of repeated measurements. We calculate the range (max - min) or standard deviation (though range is simpler here) for each student's trials.

Step2: Analyze Student A's Data

Trials for Student A: \(183.5^\circ\text{C}\), \(185.9^\circ\text{C}\), \(184.6^\circ\text{C}\)
Max = \(185.9\), Min = \(183.5\)
Range = \(185.9 - 183.5 = 2.4^\circ\text{C}\)

Step3: Analyze Student B's Data (assuming Student B's trials, though some text is unclear; wait, original table: Student B's trials? Wait, the table shows Student A: Trial1=183.5, Trial2=185.9, Trial3=184.6; Student C: Trial1=181.7, Trial2=182.0, Trial3=181.7? Wait, no, re - examine the table:

Wait, the table:

Student A: Trial1: 183.5°C, Trial2: 185.9°C, Trial3: 184.6°C

Student C: Trial1: 181.7°C, Trial2: 182.0°C, Trial3: 181.7°C

Let's recalculate ranges:

Student A: Values \(183.5\), \(185.9\), \(184.6\)
Sort: \(183.5\), \(184.6\), \(185.9\)
Range = \(185.9 - 183.5 = 2.4\)

Student C: Values \(181.7\), \(182.0\), \(181.7\)
Sort: \(181.7\), \(181.7\), \(182.0\)
Range = \(182.0 - 181.7 = 0.3\)

Wait, maybe I misread Student B. But the options include Student C. Wait, the table's Student C trials: Trial1=181.7, Trial2=182.0, Trial3=181.7. The differences between these values are very small (0.3 at max). Student A's values are more spread out (range 2.4). So Student C's data is more precise (closer together).

Answer:

Student C