Question

balance the following chemical equations: al₂o₃ + hcl → alcl₃ + 3h₂o

Explanation:

Step1: Balance Al atoms

On the left - hand side, there are 2 Al atoms in \(Al_2O_3\), and on the right - hand side, there is 1 Al atom in \(AlCl_3\). So, we put a coefficient of 2 in front of \(AlCl_3\).
\(Al_2O_3+HCl
ightarrow2AlCl_3 + 3H_2O\)

Step2: Balance Cl atoms

After putting a coefficient of 2 in front of \(AlCl_3\), there are 6 Cl atoms on the right - hand side. So, we put a coefficient of 6 in front of \(HCl\).
\(Al_2O_3+6HCl
ightarrow2AlCl_3 + 3H_2O\)

Step3: Check O and H atoms

For O atoms: There are 3 O atoms on the left (\(Al_2O_3\)) and 3 O atoms on the right (\(3H_2O\)).
For H atoms: There are 6 H atoms on the left (\(6HCl\)) and 6 H atoms on the right (\(3H_2O\)).

Answer:

\(Al_2O_3 + 6HCl=2AlCl_3+3H_2O\)