Question

balance the chemical equation by selecting the appropriate coefficient for each substance.
enter 1 if the coefficient is 1. do not leave it blank.
a.
b.
c.
d.
e. ( mathrm{al}_{2}left(mathrm{so}_{4}
ight)_{3}(a q)+mathrm{bacl}_{2}(a q)
ightarrow mathrm{baso}_{4}(s)+mathrm{alcl}_{3}(a q) )

Explanation:

Step1: Count atoms on both sides

For \(Al\): Left side has \(2\) (from \(Al_2(SO_4)_3\)), right side has \(1\) (from \(AlCl_3\)).
For \(SO_4\): Left side has \(3\) (from \(Al_2(SO_4)_3\)), right side has \(1\) (from \(BaSO_4\)).
For \(Ba\): Left side has \(1\) (from \(BaCl_2\)), right side has \(1\) (from \(BaSO_4\)).
For \(Cl\): Left side has \(2\) (from \(BaCl_2\)), right side has \(3\) (from \(AlCl_3\)).

Step2: Balance \(SO_4\)

Put coefficient \(3\) in front of \(BaSO_4\) to balance \(SO_4\) groups.
\(Al_2(SO_4)_3(aq)+BaCl_2(aq)\to3BaSO_4(s)+AlCl_3(aq)\)

Step3: Balance \(Ba\)

Put coefficient \(3\) in front of \(BaCl_2\) to balance \(Ba\) atoms.
\(Al_2(SO_4)_3(aq)+3BaCl_2(aq)\to3BaSO_4(s)+AlCl_3(aq)\)

Step4: Balance \(Al\) and \(Cl\)

Put coefficient \(2\) in front of \(AlCl_3\) to balance \(Al\) and \(Cl\) atoms.
\(Al_2(SO_4)_3(aq)+3BaCl_2(aq)\to3BaSO_4(s)+2AlCl_3(aq)\)

Answer:

\(Al_2(SO_4)_3\): \(1\), \(BaCl_2\): \(3\), \(BaSO_4\): \(3\), \(AlCl_3\): \(2\)