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a bag contains 8 red, 9 green, and 6 blue marbles. one marble is drawn …

Question

a bag contains 8 red, 9 green, and 6 blue marbles. one marble is drawn at random. what is the probability that the marble is not red?

\\(p(\text{not red}) = \quad\\%\\)

Explanation:

Find the total number of marbles

$$ \text{Total} = 8 + 9 + 6 = 23 $$

Find the number of marbles that are not red

$$ \text{Not Red} = 9 \text{ (green)} + 6 \text{ (blue)} = 15 $$

Calculate the percentage probability

$$ P(\text{not red}) = \frac{15}{23} \approx 0.65217 \approx 65.2\% $$

Answer:

A bag contains 8 red, 9 green, and 6 blue marbles. One marble is drawn at random. What is the probability that the marble is not red?

\(P(\text{not red}) =\) <blank>\(65.2\)</blank>%