Question

arrange the compounds below in decreasing order of the lonic character of the bonds in them. that is, pick 1 for the compound with the most ionic bonds, pick 2 for the compound with the next most ionic bonds, and so on. compound ionic character of bonds $\ce{cacl_{2}}$ select $\ce{nacl}$ select $\ce{alcl_{3}}$ select $\ce{pcl_{3}}$ select

Explanation:

Step1: Understand the concept of ionic character

Ionic character in a bond depends on the electronegativity difference between the atoms. The greater the electronegativity difference, the more ionic the bond.

Step2: Find electronegativity values

Electronegativity values: \(Na = 0.93\), \(Ca=1.00\), \(Al = 1.61\), \(P=2.19\), \(Cl = 3.16\)

Step3: Calculate electronegativity differences

• For \(NaCl\): \(\Delta EN=3.16 - 0.93=2.23\)
• For \(CaCl_{2}\): \(\Delta EN = 3.16-1.00 = 2.16\)
• For \(AlCl_{3}\): \(\Delta EN=3.16 - 1.61=1.55\)
• For \(PCl_{3}\): \(\Delta EN=3.16 - 2.19 = 0.97\)

Step4: Arrange based on \(\Delta EN\)

Since \(2.23>2.16>1.55>0.97\)

Answer:

\(NaCl\) (1), \(CaCl_{2}\) (2), \(AlCl_{3}\) (3), \(PCl_{3}\) (4)