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for an aqueous solution of sodium chloride, calculate the number of mol…

Question

for an aqueous solution of sodium chloride, calculate the number of moles of solute in 8.1 l of a solution with molarity 0.681 m. report your answer to two places after the decimal point.

Explanation:

Step1: Recall the formula for molarity

The formula for molarity \( M=\frac{n}{V} \), where \( M \) is molarity, \( n \) is the number of moles of solute, and \( V \) is the volume of the solution in liters. We need to solve for \( n \), so \( n = M\times V \).

Step2: Substitute the given values

Given \( M = 0.681\space M\) and \( V=8.1\space L\). Then \( n=0.681\times8.1\).

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Answer:

\( 5.52 \)