QUESTION IMAGE
Question
7x = 4x + 33; x=3; x=21; x=88; x=11
Step1: Subtract 4x from both sides
To solve the equation \(7x = 4x + 33\), we first subtract \(4x\) from both sides to get the \(x\)-terms on one side.
$$
7x - 4x = 4x + 33 - 4x
$$
Simplifying both sides, we have:
$$
3x = 33
$$
Step2: Divide both sides by 3
Next, we divide both sides of the equation \(3x = 33\) by 3 to solve for \(x\).
$$
\frac{3x}{3} = \frac{33}{3}
$$
Simplifying, we find:
$$
x = 11
$$
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\(x = 11\) (corresponding to the option with \(x = 11\))