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7x = 4x + 33; x=3; x=21; x=88; x=11

Question

7x = 4x + 33; x=3; x=21; x=88; x=11

Explanation:

Step1: Subtract 4x from both sides

To solve the equation \(7x = 4x + 33\), we first subtract \(4x\) from both sides to get the \(x\)-terms on one side.

$$ 7x - 4x = 4x + 33 - 4x $$

Simplifying both sides, we have:

$$ 3x = 33 $$

Step2: Divide both sides by 3

Next, we divide both sides of the equation \(3x = 33\) by 3 to solve for \(x\).

$$ \frac{3x}{3} = \frac{33}{3} $$

Simplifying, we find:

$$ x = 11 $$

Answer:

\(x = 11\) (corresponding to the option with \(x = 11\))