Question

a 4.60 l container with a moveable piston has a pressure of 845 mm hg. what is the pressure when the container is expanded to 10.6 l? p = ? mm hg assume that the number of moles and the temperature remain constant.

Explanation:

Step1: Use Boyle's Law formula

Boyle's Law: $P_1V_1 = P_2V_2$
Given: $P_1=845\ \text{mm Hg}$, $V_1=4.60\ \text{L}$, $V_2=10.6\ \text{L}$
Rearrange for $P_2$: $P_2 = \frac{P_1V_1}{V_2}$

Step2: Calculate $P_2$

Substitute values: $P_2 = \frac{845 \times 4.60}{10.6}$
Compute numerator: $845 \times 4.60 = 3887$
Divide by denominator: $3887 \div 10.6 \approx 366.7$

Answer:

367 (rounded to three significant figures)