Question

1.53×10³ nacl × \frac{1mol}{58.45g}

Explanation:

Step1: Identify the values

We have \( 1.53\times10^{3}\, \text{g of } NaCl \) and the molar mass of \( NaCl \) is \( 58.45\, \text{g/mol} \). The formula to find moles is \( \text{Moles} = \frac{\text{Mass}}{\text{Molar Mass}} \), so we substitute the values: \( \text{Moles} = 1.53\times 10^{3}\, \text{g} \times \frac{1\, \text{mol}}{58.45\, \text{g}} \)

Step2: Perform the calculation

First, calculate \( 1.53\times 10^{3}=1530 \). Then, \( 1530\div58.45\approx26.18 \) (rounded to two decimal places)

Answer:

The number of moles of \( NaCl \) is approximately \( 26.2\, \text{mol} \) (or more precisely \( \approx26.18\, \text{mol} \))