Question

40 bugs are in a bucket. 17 of them are ladybugs. a bug is randomly drawn from the bucket. without replacing the first one, a second bug is drawn. what is the probability that both of the bugs drawn are ladybugs? round your answer to the nearest hundredth.

Explanation:

Step1: Probability first ladybug

Total bugs = 40, ladybugs = 17. Probability: $\frac{17}{40}$

Step2: Probability second ladybug (no replacement)

Remaining bugs = 39, remaining ladybugs = 16. Probability: $\frac{16}{39}$

Step3: Multiply probabilities

$\frac{17}{40} \times \frac{16}{39} = \frac{272}{1560}$

Step4: Simplify and round

$\frac{272}{1560} \approx 0.1743 \approx 0.17$

Answer:

0.17