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Question
30 flowers are in a box. 8 of them are roses. what is the probability of drawing 2 roses if the first one is placed back in the box before the second draw? round your answer to the nearest hundredth.
Step1: Find probability of 1 rose draw
Probability = $\frac{\text{Number of roses}}{\text{Total flowers}} = \frac{8}{30}$
Step2: Calculate probability of 2 draws
Since replacement occurs, probabilities multiply: $\frac{8}{30} \times \frac{8}{30} = \frac{64}{900}$
Step3: Simplify and round
$\frac{64}{900} \approx 0.0711$, rounded to nearest hundredth is 0.07
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0.07