Question

a 230 - ml sample of a 0.295 m cacl₂ solution is left on a hot plate overnight; the following morning, the solution is 2.97 m. what volume of water evaporated from the 0.295 m cacl₂ solution? volume = ml h₂o

Explanation:

Step1: Use the dilution formula \(C_1V_1 = C_2V_2\)

Here, \(C_1 = 0.295\space M\), \(V_1=230\space mL\), \(C_2 = 2.97\space M\). We need to find \(V_2\).

$$V_2=\frac{C_1V_1}{C_2}$$

Step2: Substitute the values

$$V_2=\frac{0.295\space M\times230\space mL}{2.97\space M}$$

$$V_2=\frac{67.85}{2.97}\space mL\approx22.85\space mL$$

Step3: Calculate the volume of water evaporated

The initial volume of the solution is \(V_{initial}=230\space mL\), and the final volume of the solution is \(V_2\approx22.85\space mL\). The volume of water evaporated \(V = V_{initial}-V_2\)

$$V = 230 - 22.85=207.15\space mL$$

Answer:

\(207\space mL\)