Question

1s/23 which electron configuration belongs to chlorine (cl)? 1s²2s²2p⁶3s²3p⁵ 1s²2s²2p⁶3s²3p⁶ 1s²2s²2p⁶3s²3p⁷

Explanation:

Step1: Determine the atomic number of Chlorine

Chlorine (\(Cl\)) has an atomic number of \(17\).

Step2: Calculate the total number of electrons in each configuration

• For \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}\): \(2 + 2+6 + 2+5=17\)
• For \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\): \(2 + 2+6 + 2+6 = 18\)
• For \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{7}\): \(2 + 2+6 + 2+7=19\)

Step3: Match with Chlorine's electron count

Since Chlorine has \(17\) electrons, the configuration \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}\) is correct.

Answer:

A. \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}\)