QUESTION IMAGE
Question
if 18.5 grams of \\(\text{cucl}_2\\) react with 22.8 grams of \\(\text{nano}_3\\), what mass of \\(\text{nacl}\\) can be formed?
\\(\text{cucl}_2 + 2\text{nano}_3 \
ightarrow \text{cu(no}_3)_2 + 2\text{nacl}\\)
- 12.4 g nacl
- 15.7 g nacl
- 16.2 g nacl
- 28.4 g nacl
Calculate moles of each reactant
$$
LATEXBLOCK0
$$
Determine the limiting reactant
$$
LATEXBLOCK1
$$
Calculate the mass of NaCl formed
$$
LATEXBLOCK2
$$
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- (A) 12.4 g NaCl
- (B) 15.7 g NaCl (Correct answer)
- (C) 16.2 g NaCl
- (D) 28.4 g NaCl