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18. in 1920, a certain countrys population was 73,700,939, and its area…

Question

  1. in 1920, a certain countrys population was 73,700,939, and its area was 2,940,654 square miles. find the population density of the country, to the nearest tenth, expressed in people per square kilometer.

the population density in 1920 was approximately (1)
(round to the nearest tenth as needed.)
(1) o people per cubic kilometer.
o people per kilometer.
o people per square kilometer.

  1. find the population density, to the nearest tenth, for each of the following states. which state has the greater population density? how many more people per square mile inhabit the state with the greater density than inhabit the state with the lesser density?

state a population: 12,771,859 area: 58,236 mi²
state b population: 11,723,929 area: 41,538 mi²
the population density for state a is (1)
(round to the nearest tenth as needed.)
the population density for state b is (2)
(round to the nearest tenth as needed.)
which state has the greater population density? how many more people per square mile inhabit the state with the greater density than inhabit the state with the lesser density? choose the correct answer below and fill in the answer box to complete your answer.
(round to the nearest tenth as needed.)
o a. state b has the greater population density by people per square mile.
o b. state a has the greater population density by people per square mile.
(1) o people per square mile. (2) o people per square mile.
o people per mile. o people per cubic mile.
o people per cubic mile. o people per mile.

Explanation:

Problem 17

Step1: Calcular la densidad de población para el Estado A

La fórmula para la densidad de población es \( \text{Densidad}=\frac{\text{Población}}{\text{Área}} \).
Para el Estado A, la población es \( P_A = 12771859 \) y el área \( A_A=58236\ mi^{2} \).
Entonces, \( D_A=\frac{12771859}{58236}\approx219.3 \)

Step2: Calcular la densidad de población para el Estado B

Para el Estado B, la población es \( P_B = 11723929 \) y el área \( A_B = 41538\ mi^{2} \).
Entonces, \( D_B=\frac{11723929}{41538}\approx282.2 \)

Step3: Comparar las densidades

Calculamos la diferencia \( D_B - D_A=282.2 - 219.3 = 62.9 \)

Answer:

El Estado B tiene la mayor densidad de población.

  • La densidad de población para el Estado A es \( 219.3 \) personas por milla cuadrada.
  • La densidad de población para el Estado B es \( 282.2 \) personas por milla cuadrada.
  • \( A. \) Estado B tiene la mayor densidad de población por \( 62.9 \) personas por milla cuadrada.