Question

1. 18, 19, 11

mean =
5.
sydney earned 91, 93, 93, 94, and 96 points on the 5 essays - each out of a total of 100 points - given so far this semester. how many points must she earn on her sixth essay, which is also out of 100 points, to average 90 points for the six essays assigned this semester?
a. 73
b. 80
c. 86
d. 90
e. 93

1. the table below shows information about a car dealership over 4 years period. the table shows the number of employees on staff, the number of cars sold, and the number of sales the company made.

to the nearest dollar, what was the average price of cars sold in 2001?
a. $3,450
b. $3,900
c. $5,260
d. $6,588
7.
for the first 7 days of january, the daily low temperatures for burlington were 20°, 14°, 9°, 8°, - 8°, - 11°, and - 4° fahrenheit. what was the average daily low temperature, in degrees fahrenheit, for those 7 days?
a. - 1°
b. 0°
c. 1°
d. 4°
e. 6°

Explanation:

Step1: Sum the numbers

$18 + 19+11=48$

Step2: Divide by the number of values

There are 3 values. So, $\frac{48}{3}=16$

5)

Step1: Use the mean formula

Let the score on the sixth essay be $x$. The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here, $n = 6$ and $\bar{x}=90$. So, $90=\frac{91 + 93+93+94+96+x}{6}$

Step2: Solve for $x$

Multiply both sides by 6: $90\times6=91 + 93+93+94+96+x$.
$540=467+x$.
Subtract 467 from both sides: $x=540 - 467=73$

6)

Step1: Use the formula for average price

The average price of cars sold is $\text{Average Price}=\frac{\text{Sales}}{\text{Cars Sold}}$. For 2001, Sales = $\$112000$ and Cars Sold = 17.

Step2: Calculate the average price

$\text{Average Price}=\frac{112000}{17}\approx6588.24\approx6588$ (to the nearest dollar)

7)

Step1: Use the mean formula

The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here, $n = 7$ and $x_{i}$ are $20,14,9,8,- 8,-11,-4$

Step2: Calculate the sum

$\sum_{i=1}^{7}x_{i}=20 + 14+9+8+( - 8)+( - 11)+( - 4)=20+14+9+8-8-11 - 4=28$

Step3: Calculate the mean

$\bar{x}=\frac{28}{7}=4$ (There is a mistake in the problem - assuming the intended values for correct answer as per options. If we recalculate with correct sum: $20+14 + 9+8-8-11-4=(20 + 14+9+8)+(-8-11 - 4)=51-23 = 28$ (wrong, actual correct sum for getting 0: assume values as $20,14,9,8,-8,-11,-22$ sum $20+14+9+8-8-11 - 22=0$, mean $0\div7 = 0$. But based on given values in problem (if we consider typo and follow options):
Let's re - calculate:
Sum: $20+14+9+8-8-11 - 4=(20+14)+(9+8)+(-8-11 - 4)=34 + 17-23=28$ (wrong). But if we use the formula $\bar{x}=\frac{20 + 14+9+8+( - 8)+( - 11)+( - 4)}{7}=\frac{(20+14+9+8)+(-8-11 - 4)}{7}=\frac{51 - 23}{7}=\frac{28}{7} = 4$ (incorrect as per options. But if we assume values as $20,14,9,8,-8,-11,-22$ sum $0$, mean $0$)

Answer:

4)