17) c₄h₈fcooh # of molecules:______ # of elements:______ name of element: # of atoms:______ ______ ______ ______ total # of atoms:______ the #4 is a (coefficient or subscript) 18) 2(nh₄)₃po₄ # of molecules:______ # of elements:______ name of element: # of atoms:______ ______ ______ ______ total # of atoms:______ the #2 is a (coefficient or subscript)

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Accepted Answer

# Explanation:
## Step1: Analyze $C_4H_8FCOOH$
- **Number of molecules**: Since there is no coefficient in front of $C_4H_8FCOOH$, the number of molecules is $1$.
- **Number of elements**: The elements present are $C$ (Carbon), $H$ (Hydrogen), $F$ (Fluorine), $O$ (Oxygen). So, the number of elements is $4$.
- **Number of atoms**:
    - For $C$: In $C_4H_8FCOOH$, we have $C_4$ and $C$ (from $COOH$), so total $C$ atoms $=4 + 1=5$.
    - For $H$: We have $H_8$ and $H$ (from $COOH$), so total $H$ atoms $=8+1 = 9$.
    - For $F$: There is $1$ $F$ atom.
    - For $O$: There are $2$ $O$ atoms (from $COOH$).
    - Total number of atoms $=5 + 9+1 + 2=17$.
    - The $4$ in $C_4$ is a subscript as it indicates the number of $C$ atoms in a part of the molecule.

## Step2: Analyze $2(NH_4)_3PO_4$
- **Number of molecules**: The coefficient $2$ in front of $(NH_4)_3PO_4$ indicates the number of molecules, so it is $2$.
- **Number of elements**: The elements present are $N$ (Nitrogen), $H$ (Hydrogen), $P$ (Phosphorus), $O$ (Oxygen). So, the number of elements is $4$.
- **Number of atoms**:
    - For $N$: In $(NH_4)_3$, we have $3\times1 = 3$ $N$ atoms per $(NH_4)_3PO_4$ molecule, and with $2$ molecules, $N$ atoms $=2\times3=6$.
    - For $H$: In $(NH_4)_3$, we have $3\times4 = 12$ $H$ atoms per $(NH_4)_3PO_4$ molecule, and with $2$ molecules, $H$ atoms $=2\times12 = 24$.
    - For $P$: There is $1$ $P$ atom per $(NH_4)_3PO_4$ molecule, and with $2$ molecules, $P$ atoms $=2\times1=2$.
    - For $O$: In $PO_4$, we have $4$ $O$ atoms per $(NH_4)_3PO_4$ molecule, and with $2$ molecules, $O$ atoms $=2\times4=8$.
    - Total number of atoms $=6+24 + 2+8=40$.
    - The $2$ in front of $(NH_4)_3PO_4$ is a coefficient as it indicates the number of $(NH_4)_3PO_4$ molecules.

# Answer:
17)
- # of molecules: $1$
- # of elements: $4$
- Name of element: $C$, # of atoms: $5$; $H$, # of atoms: $9$; $F$, # of atoms: $1$; $O$, # of atoms: $2$
- Total # of atoms: $17$
- The #4 is a subscript.

18)
- # of molecules: $2$
- # of elements: $4$
- Name of element: $N$, # of atoms: $6$; $H$, # of atoms: $24$; $P$, # of atoms: $2$; $O$, # of atoms: $8$
- Total # of atoms: $40$
- The #2 is a coefficient.

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Explanation:

Step1: Analyze \(C_4H_8FCOOH\)

Step2: Analyze \(2(NH_4)_3PO_4\)

Answer: