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Question
16 multiple choice 0.5 points what is the oxidation number of br in nabro? 3 4 2 -1 -2 -3 5 1 clear my selection
Step1: Determine oxidation numbers of known elements
In \(NaBrO\), sodium (\(Na\)) has an oxidation number of \(+ 1\) (as it is in group 1 of the periodic table and typically has an oxidation number of \(+1\) in compounds), and oxygen (\(O\)) has an oxidation number of \(-2\) (as it typically has an oxidation number of \(-2\) in compounds).
Step2: Set up the equation for the sum of oxidation numbers
Let the oxidation number of \(Br\) be \(x\). For a neutral compound, the sum of the oxidation numbers of all atoms is \(0\). So we have the equation \((+1)+x+(-2)=0\).
Step3: Solve the equation for \(x\)
Simplify the equation: \(1 + x-2=0\), which becomes \(x - 1=0\). Solving for \(x\) gives \(x = 1\).
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