Question

a 15.0 l tank of gas is contained at a high pressure of 8.20 × 10⁴ torr. the tank is opened and the gas expands into an empty chamber with a volume of 6.00 × 10⁴ l. calculate the new pressure of the gas.______ torryour answer should be rounded to three significant figures. do not include units in your answer.

Explanation:

Step1: Write Boyle's Law formula

Boyle's Law is \(P_1V_1 = P_2V_2\), where \(P_1\) is initial pressure, \(V_1\) is initial volume, \(P_2\) is final pressure, and \(V_2\) is final volume.

Step2: Rearrange formula for \(P_2\)

\(P_2=\frac{P_1V_1}{V_2}\)

Step3: Substitute values

Given \(P_1 = 8.20\times10^{4}\) torr, \(V_1=15.0\space L\), \(V_2 = 6.00\times 10^{4}\space L\).
\(P_2=\frac{(8.20\times 10^{4})\times15.0}{6.00\times 10^{4}}\)
\(P_2=\frac{8.20\times15.0}{6.00}\)
\(P_2=\frac{123}{6.00}=20.5\)

Answer:

20.5